What Is the Color of Iodine in Different States?

Iodine (I, atomic number 53) is a halogen. Unlike most elements, iodine’s color changes dramatically depending on its physical state or the medium in which it is dissolved. This variability, ranging from metallic gray to deep violet to dark brown, results from how the iodine molecule interacts with its surroundings.

The Color of Solid and Gaseous Iodine

In its pure, elemental state, solid iodine exists as crystalline purplish-black or grayish-black crystals at room temperature. The solid form possesses a noticeable metallic sheen, which is unusual for a non-metal.

When heated, solid iodine undergoes sublimation, transforming directly into a gas without melting. The resulting vapor is a vibrant, deep violet or purple color. This striking vapor is the classic visual associated with the element, and its name is derived from the Greek word ioeides, meaning violet.

Appearance in Common Medical and Lab Solutions

The color of iodine changes significantly when dissolved in different solvents for practical applications. Tinctures of iodine, commonly used as antiseptics, are solutions of iodine and potassium iodide dissolved in alcohol and water. These solutions are a familiar reddish-brown or deep brown color.

A simple aqueous solution, where elemental iodine is dissolved in water, appears yellowish-brown. While molecular iodine (I₂) is not highly soluble in water, adding iodide ions (I⁻) allows it to dissolve more readily. The iodide ions combine with iodine molecules to form triiodide ions (\(I_3^-\)), which cause the brown coloration.

A notable color change occurs in the classic chemical test for starch. When an iodine solution is added to starch, the color instantly transforms into a vivid, deep blue-black. This striking color results from polyiodide chains becoming trapped inside the helical structure of the starch molecule, amylose.

The Scientific Reason for Color Variation

The color we perceive is determined by which wavelengths of visible light a substance absorbs and which ones it reflects or transmits. For molecular iodine (\(I_2\)), its intrinsic color is governed by the energy required for its electrons to jump to a higher energy level, an electronic transition. In the gaseous state, where the \(I_2\) molecule is isolated, this transition absorbs light in the blue-green part of the spectrum, causing the complementary color, violet, to be seen.

When iodine is dissolved, the solvent molecules interact with the \(I_2\) molecule, a process known as solvation. This interaction alters the energy gap between the electron energy levels. Non-polar solvents, such as hydrocarbons, interact weakly with the \(I_2\) molecule, resulting in a solution that maintains the characteristic violet color similar to the vapor.

Polar solvents, like water and alcohol, interact much more strongly, forming weak associations called charge-transfer complexes. This complex formation significantly lowers the energy needed for the electron transition. The lower energy requirement means the complex absorbs light at longer wavelengths, shifting the absorption from the blue-green region toward the yellow-brown region of the spectrum. This shift in absorbed light is why iodine solutions in polar solvents appear brown to the human eye.